C17H19Ir
1 compound has this formula on CompoundList.
- Molar mass
- 415.56g/mol
- Monoisotopic mass
- 416.1116Da
- Atoms
- 37
- Elements
- 3
The formula C17H19Ir describes a molecule made of 17 carbon atoms, 19 hydrogen atoms and 1 iridium atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1749.14%12.011 × 17 = 204.187 g/mol
- H Hydrogen × 194.61%1.008 × 19 = 19.152 g/mol
- Ir Iridium × 146.26%192.22 × 1 = 192.220 g/mol
Compounds with the formula C17H19Ir
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C17H19Ir?
The molar mass of C17H19Ir is 415.56 g/mol, calculated from standard atomic weights for 17 carbon atoms, 19 hydrogen atoms and 1 iridium atom. The monoisotopic mass is 416.1116 Da.
How many compounds have the formula C17H19Ir?
CompoundList lists 1 compound with the molecular formula C17H19Ir, including (1,5-Cyclooctadiene)-eta5-indenyl)iridium(I). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.