CompoundList
Molecular formula

C18Br14O2

2 compounds have this formula on CompoundList.

Molar mass
1366.85g/mol
Monoisotopic mass
1352.8465Da
Atoms
34
Elements
3
Rings plus double bonds
12

The formula C18Br14O2 describes a molecule made of 18 carbon atoms, 14 bromine atoms and 2 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1815.82%
    12.011 × 18 = 216.198 g/mol
  • Br Bromine × 1481.84%
    79.904 × 14 = 1118.656 g/mol
  • O Oxygen × 22.34%
    15.999 × 2 = 31.998 g/mol
Look up another formula

Compounds with the formula C18Br14O2

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 2 of 2 compounds

Frequently asked questions

What is the molar mass of C18Br14O2?

The molar mass of C18Br14O2 is 1366.85 g/mol, calculated from standard atomic weights for 18 carbon atoms, 14 bromine atoms and 2 oxygen atoms. The monoisotopic mass is 1352.8465 Da.

How many compounds have the formula C18Br14O2?

CompoundList lists 2 compounds with the molecular formula C18Br14O2, including Tetradecabromo-1,4-diphenoxybenzene, 1,1'-[(3,4,5,6-Tetrabromo-1,2-phenylene)bis(oxy)]bis(pentabromobenzene). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C18Br14O2?

C18Br14O2 has a degree of unsaturation of 12. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.