CompoundList
Molecular formula

C18H13ClFN3O

16 compounds have this formula on CompoundList.

Molar mass
341.77g/mol
Monoisotopic mass
347.0932Da
Atoms
37
Elements
6
Rings plus double bonds
13

The formula C18H13ClFN3O describes a molecule made of 18 carbon atoms, 13 hydrogen atoms, 1 chlorine atom, 1 fluorine atom, 3 nitrogen atoms and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1863.26%
    12.011 × 18 = 216.198 g/mol
  • H Hydrogen × 133.83%
    1.008 × 13 = 13.104 g/mol
  • Cl Chlorine × 110.37%
    35.45 × 1 = 35.450 g/mol
  • F Fluorine × 15.56%
    18.998 × 1 = 18.998 g/mol
  • N Nitrogen × 312.30%
    14.007 × 3 = 42.021 g/mol
  • O Oxygen × 14.68%
    15.999 × 1 = 15.999 g/mol
Look up another formula

Compounds with the formula C18H13ClFN3O

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 16 of 16 compounds

Frequently asked questions

What is the molar mass of C18H13ClFN3O?

The molar mass of C18H13ClFN3O is 341.77 g/mol, calculated from standard atomic weights for 18 carbon atoms, 13 hydrogen atoms, 1 chlorine atom, 1 fluorine atom, 3 nitrogen atoms and 1 oxygen atom. The monoisotopic mass is 347.0932 Da.

How many compounds have the formula C18H13ClFN3O?

CompoundList lists 16 compounds with the molecular formula C18H13ClFN3O, including 1'-Hydroxymidazolam, 4-Hydroxymidazolam, 1'-Hydroxy midazolam-13C3. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C18H13ClFN3O?

C18H13ClFN3O has a degree of unsaturation of 13. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.