C18H14BrFS
3 compounds have this formula on CompoundList.
- Molar mass
- 361.27g/mol
- Monoisotopic mass
- 359.9984Da
- Atoms
- 35
- Elements
- 5
- Rings plus double bonds
- 11
The formula C18H14BrFS describes a molecule made of 18 carbon atoms, 14 hydrogen atoms, 1 bromine atom, 1 fluorine atom and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1859.84%12.011 × 18 = 216.198 g/mol
- H Hydrogen × 143.91%1.008 × 14 = 14.112 g/mol
- Br Bromine × 122.12%79.904 × 1 = 79.904 g/mol
- F Fluorine × 15.26%18.998 × 1 = 18.998 g/mol
- S Sulfur × 18.87%32.06 × 1 = 32.060 g/mol
Compounds with the formula C18H14BrFS
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 3 of 3 compounds
Frequently asked questions
What is the molar mass of C18H14BrFS?
The molar mass of C18H14BrFS is 361.27 g/mol, calculated from standard atomic weights for 18 carbon atoms, 14 hydrogen atoms, 1 bromine atom, 1 fluorine atom and 1 sulfur atom. The monoisotopic mass is 359.9984 Da.
How many compounds have the formula C18H14BrFS?
CompoundList lists 3 compounds with the molecular formula C18H14BrFS, including 2-(5-Bromo-2-methylbenzyl)-5-(4-fluorophenyl)thiophene, 2-(4-Bromo-2-methylbenzyl)-5-(4-fluorophenyl)thiophene, (4-Fluorophenyl)diphenylsulfonium bromide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C18H14BrFS?
C18H14BrFS has a degree of unsaturation of 11. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.