CompoundList
Molecular formula

C18H15BrFNO

8 compounds have this formula on CompoundList.

Molar mass
360.23g/mol
Monoisotopic mass
359.0321Da
Atoms
37
Elements
6
Rings plus double bonds
11

The formula C18H15BrFNO describes a molecule made of 18 carbon atoms, 15 hydrogen atoms, 1 bromine atom, 1 fluorine atom, 1 nitrogen atom and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1860.02%
    12.011 × 18 = 216.198 g/mol
  • H Hydrogen × 154.20%
    1.008 × 15 = 15.120 g/mol
  • Br Bromine × 122.18%
    79.904 × 1 = 79.904 g/mol
  • F Fluorine × 15.27%
    18.998 × 1 = 18.998 g/mol
  • N Nitrogen × 13.89%
    14.007 × 1 = 14.007 g/mol
  • O Oxygen × 14.44%
    15.999 × 1 = 15.999 g/mol
Look up another formula

Compounds with the formula C18H15BrFNO

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 8 of 8 compounds

Frequently asked questions

What is the molar mass of C18H15BrFNO?

The molar mass of C18H15BrFNO is 360.23 g/mol, calculated from standard atomic weights for 18 carbon atoms, 15 hydrogen atoms, 1 bromine atom, 1 fluorine atom, 1 nitrogen atom and 1 oxygen atom. The monoisotopic mass is 359.0321 Da.

How many compounds have the formula C18H15BrFNO?

CompoundList lists 8 compounds with the molecular formula C18H15BrFNO, including 4-(5-Bromo-2-fluorophenyl)-1,3,4,6,7,8-hexahydrocyclopenta[g]quinolin-2-one, (4-Bromo-3-fluorophenyl)(3-((2,5-dihydro-1H-pyrrol-1-yl)methyl)phenyl)methanone, (4-Bromo-3-fluorophenyl)(4-((2,5-dihydro-1H-pyrrol-1-yl)methyl)phenyl)methanone. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C18H15BrFNO?

C18H15BrFNO has a degree of unsaturation of 11. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.