Molecular formula

C₁₈H₃₂N₂O₄Si

3 compounds have this formula on CompoundList.

Molar mass: 368.55g/mol
Monoisotopic mass: 368.2131Da
Atoms: 57
Elements: 5
Rings plus double bonds: 5

The formula C18H32N2O4Si describes a molecule made of 18 carbon atoms, 32 hydrogen atoms, 2 nitrogen atoms, 4 oxygen atoms and 1 silicon atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

C Carbon × 1858.66%
12.011 × 18 = 216.198 g/mol
H Hydrogen × 328.75%
1.008 × 32 = 32.256 g/mol
N Nitrogen × 27.60%
14.007 × 2 = 28.014 g/mol
O Oxygen × 417.36%
15.999 × 4 = 63.996 g/mol
Si Silicon × 17.62%
28.085 × 1 = 28.085 g/mol

Look up another formula

Compounds with the formula C18H32N2O4Si

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 3 of 3 compounds

Urea, N-(1-phenylethyl)-N'-(3-(triethoxysilyl)propyl)-

CAS 68959-21-7C₁₈H₃₂N₂O₄Si

1-[(R)-1-Phenylethyl]-3-[3-(triethoxysilyl)propyl]urea

CAS 131206-15-0C₁₈H₃₂N₂O₄Si

Ethyl 6-methoxy-6-methyl-1-(2-trimethylsilylethoxymethyl)-5,7-dihydro-4H-indazole-3-carboxylate

CAS 2920407-49-2C₁₈H₃₂N₂O₄Si

Frequently asked questions

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What is the molar mass of C18H32N2O4Si?

The molar mass of C18H32N2O4Si is 368.55 g/mol, calculated from standard atomic weights for 18 carbon atoms, 32 hydrogen atoms, 2 nitrogen atoms, 4 oxygen atoms and 1 silicon atom. The monoisotopic mass is 368.2131 Da.

How many compounds have the formula C18H32N2O4Si?

CompoundList lists 3 compounds with the molecular formula C18H32N2O4Si, including Urea, N-(1-phenylethyl)-N'-(3-(triethoxysilyl)propyl)-, 1-[(R)-1-Phenylethyl]-3-[3-(triethoxysilyl)propyl]urea, Ethyl 6-methoxy-6-methyl-1-(2-trimethylsilylethoxymethyl)-5,7-dihydro-4H-indazole-3-carboxylate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C18H32N2O4Si?

C18H32N2O4Si has a degree of unsaturation of 5. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.