C19H10F6O8
1 compound has this formula on CompoundList.
- Molar mass
- 480.27g/mol
- Monoisotopic mass
- 480.0280Da
- Atoms
- 43
- Elements
- 4
- Rings plus double bonds
- 12
The formula C19H10F6O8 describes a molecule made of 19 carbon atoms, 10 hydrogen atoms, 6 fluorine atoms and 8 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1947.52%12.011 × 19 = 228.209 g/mol
- H Hydrogen × 102.10%1.008 × 10 = 10.080 g/mol
- F Fluorine × 623.73%18.998 × 6 = 113.988 g/mol
- O Oxygen × 826.65%15.999 × 8 = 127.992 g/mol
Compounds with the formula C19H10F6O8
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
![1,2-Benzenedicarboxylic acid, 4,4'-[2,2,2-trifluoro-1-(trifluoromethyl)ethylidene]bis- chemical structure, C19H10F6O8, CAS 3016-76-0](/s/APXJLYIVOFARRM-UHFFFAOYSA-N.svg)
Frequently asked questions
What is the molar mass of C19H10F6O8?
The molar mass of C19H10F6O8 is 480.27 g/mol, calculated from standard atomic weights for 19 carbon atoms, 10 hydrogen atoms, 6 fluorine atoms and 8 oxygen atoms. The monoisotopic mass is 480.0280 Da.
How many compounds have the formula C19H10F6O8?
CompoundList lists 1 compound with the molecular formula C19H10F6O8, including 1,2-Benzenedicarboxylic acid, 4,4'-[2,2,2-trifluoro-1-(trifluoromethyl)ethylidene]bis-. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C19H10F6O8?
C19H10F6O8 has a degree of unsaturation of 12. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.