C19H23Cl2N5O
15 compounds have this formula on CompoundList.
- Molar mass
- 408.33g/mol
- Monoisotopic mass
- 413.1656Da
- Atoms
- 50
- Elements
- 5
- Rings plus double bonds
- 10
The formula C19H23Cl2N5O describes a molecule made of 19 carbon atoms, 23 hydrogen atoms, 2 chlorine atoms, 5 nitrogen atoms and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1955.89%12.011 × 19 = 228.209 g/mol
- H Hydrogen × 235.68%1.008 × 23 = 23.184 g/mol
- Cl Chlorine × 217.36%35.45 × 2 = 70.900 g/mol
- N Nitrogen × 517.15%14.007 × 5 = 70.035 g/mol
- O Oxygen × 13.92%15.999 × 1 = 15.999 g/mol
Compounds with the formula C19H23Cl2N5O
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 15 of 15 compounds
Frequently asked questions
What is the molar mass of C19H23Cl2N5O?
The molar mass of C19H23Cl2N5O is 408.33 g/mol, calculated from standard atomic weights for 19 carbon atoms, 23 hydrogen atoms, 2 chlorine atoms, 5 nitrogen atoms and 1 oxygen atom. The monoisotopic mass is 413.1656 Da.
How many compounds have the formula C19H23Cl2N5O?
CompoundList lists 15 compounds with the molecular formula C19H23Cl2N5O, including Trazodone hydrochloride, Trazodone-d6 hydrochloride, 4-Chloro trazodone isomer hydrochloride. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C19H23Cl2N5O?
C19H23Cl2N5O has a degree of unsaturation of 10. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.