CompoundList
Molecular formula

C19H38ClNO4

5 compounds have this formula on CompoundList.

Molar mass
379.97g/mol
Monoisotopic mass
388.3054Da
Atoms
63
Elements
5
Rings plus double bonds
1

The formula C19H38ClNO4 describes a molecule made of 19 carbon atoms, 38 hydrogen atoms, 1 chlorine atom, 1 nitrogen atom and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1960.06%
    12.011 × 19 = 228.209 g/mol
  • H Hydrogen × 3810.08%
    1.008 × 38 = 38.304 g/mol
  • Cl Chlorine × 19.33%
    35.45 × 1 = 35.450 g/mol
  • N Nitrogen × 13.69%
    14.007 × 1 = 14.007 g/mol
  • O Oxygen × 416.84%
    15.999 × 4 = 63.996 g/mol
Look up another formula

Compounds with the formula C19H38ClNO4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 5 of 5 compounds

Frequently asked questions

What is the molar mass of C19H38ClNO4?

The molar mass of C19H38ClNO4 is 379.97 g/mol, calculated from standard atomic weights for 19 carbon atoms, 38 hydrogen atoms, 1 chlorine atom, 1 nitrogen atom and 4 oxygen atoms. The monoisotopic mass is 388.3054 Da.

How many compounds have the formula C19H38ClNO4?

CompoundList lists 5 compounds with the molecular formula C19H38ClNO4, including Lauroyl-d3-L-carnitine Hydrochloride, DL-Lauroylcarnitine chloride, Lauroyllevocarnitine hydrochloride. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C19H38ClNO4?

C19H38ClNO4 has a degree of unsaturation of 1. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.