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Molecular formula

C21H12F3N5OS3

1 compound has this formula on CompoundList.

Molar mass
503.54g/mol
Monoisotopic mass
503.0156Da
Atoms
45
Elements
6
Rings plus double bonds
17

The formula C21H12F3N5OS3 describes a molecule made of 21 carbon atoms, 12 hydrogen atoms, 3 fluorine atoms, 5 nitrogen atoms, 1 oxygen atom and 3 sulfur atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2150.09%
    12.011 × 21 = 252.231 g/mol
  • H Hydrogen × 122.40%
    1.008 × 12 = 12.096 g/mol
  • F Fluorine × 311.32%
    18.998 × 3 = 56.994 g/mol
  • N Nitrogen × 513.91%
    14.007 × 5 = 70.035 g/mol
  • O Oxygen × 13.18%
    15.999 × 1 = 15.999 g/mol
  • S Sulfur × 319.10%
    32.06 × 3 = 96.180 g/mol
Look up another formula

Compounds with the formula C21H12F3N5OS3

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

2-{[3-Cyano-6-(2-thienyl)-4-(trifluoromethyl)-2-pyridinyl]sulfanyl}-N-(5-phenyl-1,3,4-thiadiazol-2-yl)acetamide chemical structure, C21H12F3N5OS3, CAS 309745-18-4
2-{[3-Cyano-6-(2-thienyl)-4-(trifluoromethyl)-2-pyridinyl]sulfanyl}-N-(5-phenyl-1,3,4-thiadiazol-2-yl)acetamide
CAS 309745-18-4C21H12F3N5OS3

Frequently asked questions

What is the molar mass of C21H12F3N5OS3?

The molar mass of C21H12F3N5OS3 is 503.54 g/mol, calculated from standard atomic weights for 21 carbon atoms, 12 hydrogen atoms, 3 fluorine atoms, 5 nitrogen atoms, 1 oxygen atom and 3 sulfur atoms. The monoisotopic mass is 503.0156 Da.

How many compounds have the formula C21H12F3N5OS3?

CompoundList lists 1 compound with the molecular formula C21H12F3N5OS3, including 2-{[3-Cyano-6-(2-thienyl)-4-(trifluoromethyl)-2-pyridinyl]sulfanyl}-N-(5-phenyl-1,3,4-thiadiazol-2-yl)acetamide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C21H12F3N5OS3?

C21H12F3N5OS3 has a degree of unsaturation of 17. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.