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Molecular formula

C21H13Cl2F3N4O4

1 compound has this formula on CompoundList.

Molar mass
513.25g/mol
Monoisotopic mass
512.0266Da
Atoms
47
Elements
6
Rings plus double bonds
15

The formula C21H13Cl2F3N4O4 describes a molecule made of 21 carbon atoms, 13 hydrogen atoms, 2 chlorine atoms, 3 fluorine atoms, 4 nitrogen atoms and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2149.14%
    12.011 × 21 = 252.231 g/mol
  • H Hydrogen × 132.55%
    1.008 × 13 = 13.104 g/mol
  • Cl Chlorine × 213.81%
    35.45 × 2 = 70.900 g/mol
  • F Fluorine × 311.10%
    18.998 × 3 = 56.994 g/mol
  • N Nitrogen × 410.92%
    14.007 × 4 = 56.028 g/mol
  • O Oxygen × 412.47%
    15.999 × 4 = 63.996 g/mol
Look up another formula

Compounds with the formula C21H13Cl2F3N4O4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

N-[1-Benzyl-2,4,6-trioxo-5-(trifluoromethyl)-7H-pyrrolo[2,3-d]pyrimidin-5-yl]-2,4-dichlorobenzamide chemical structure, C21H13Cl2F3N4O4, CAS 524716-42-5
N-[1-Benzyl-2,4,6-trioxo-5-(trifluoromethyl)-7H-pyrrolo[2,3-d]pyrimidin-5-yl]-2,4-dichlorobenzamide
CAS 524716-42-5C21H13Cl2F3N4O4

Frequently asked questions

What is the molar mass of C21H13Cl2F3N4O4?

The molar mass of C21H13Cl2F3N4O4 is 513.25 g/mol, calculated from standard atomic weights for 21 carbon atoms, 13 hydrogen atoms, 2 chlorine atoms, 3 fluorine atoms, 4 nitrogen atoms and 4 oxygen atoms. The monoisotopic mass is 512.0266 Da.

How many compounds have the formula C21H13Cl2F3N4O4?

CompoundList lists 1 compound with the molecular formula C21H13Cl2F3N4O4, including N-[1-Benzyl-2,4,6-trioxo-5-(trifluoromethyl)-7H-pyrrolo[2,3-d]pyrimidin-5-yl]-2,4-dichlorobenzamide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C21H13Cl2F3N4O4?

C21H13Cl2F3N4O4 has a degree of unsaturation of 15. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.