CompoundList
Molecular formula

C21H17ClF3N3O

10 compounds have this formula on CompoundList.

Molar mass
419.83g/mol
Monoisotopic mass
419.1012Da
Atoms
46
Elements
6
Rings plus double bonds
13

The formula C21H17ClF3N3O describes a molecule made of 21 carbon atoms, 17 hydrogen atoms, 1 chlorine atom, 3 fluorine atoms, 3 nitrogen atoms and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2160.08%
    12.011 × 21 = 252.231 g/mol
  • H Hydrogen × 174.08%
    1.008 × 17 = 17.136 g/mol
  • Cl Chlorine × 18.44%
    35.45 × 1 = 35.450 g/mol
  • F Fluorine × 313.58%
    18.998 × 3 = 56.994 g/mol
  • N Nitrogen × 310.01%
    14.007 × 3 = 42.021 g/mol
  • O Oxygen × 13.81%
    15.999 × 1 = 15.999 g/mol
Look up another formula

Compounds with the formula C21H17ClF3N3O

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 10 of 10 compounds

Frequently asked questions

What is the molar mass of C21H17ClF3N3O?

The molar mass of C21H17ClF3N3O is 419.83 g/mol, calculated from standard atomic weights for 21 carbon atoms, 17 hydrogen atoms, 1 chlorine atom, 3 fluorine atoms, 3 nitrogen atoms and 1 oxygen atom. The monoisotopic mass is 419.1012 Da.

How many compounds have the formula C21H17ClF3N3O?

CompoundList lists 10 compounds with the molecular formula C21H17ClF3N3O, including 1-{1-[3-Chloro-5-(trifluoromethyl)-2-pyridinyl]-1H-indol-3-yl}-5-(dimethylamino)-1,4-pentadien-3-one, (6-Chloro-4-((3-(trifluoromethyl)phenyl)amino)quinolin-3-yl)(pyrrolidin-1-yl)methanone, 4-Chloro-N-[4-(2-dimethylamino-5-trifluoromethyl-pyridin-3-yl)-phenyl]-benzamide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C21H17ClF3N3O?

C21H17ClF3N3O has a degree of unsaturation of 13. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.