CompoundList
Molecular formula

C21H22N4O8

9 compounds have this formula on CompoundList.

Molar mass
458.43g/mol
Monoisotopic mass
458.1438Da
Atoms
55
Elements
4
Rings plus double bonds
13

The formula C21H22N4O8 describes a molecule made of 21 carbon atoms, 22 hydrogen atoms, 4 nitrogen atoms and 8 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2155.02%
    12.011 × 21 = 252.231 g/mol
  • H Hydrogen × 224.84%
    1.008 × 22 = 22.176 g/mol
  • N Nitrogen × 412.22%
    14.007 × 4 = 56.028 g/mol
  • O Oxygen × 827.92%
    15.999 × 8 = 127.992 g/mol
Look up another formula

Compounds with the formula C21H22N4O8

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 9 of 9 compounds

Frequently asked questions

What is the molar mass of C21H22N4O8?

The molar mass of C21H22N4O8 is 458.43 g/mol, calculated from standard atomic weights for 21 carbon atoms, 22 hydrogen atoms, 4 nitrogen atoms and 8 oxygen atoms. The monoisotopic mass is 458.1438 Da.

How many compounds have the formula C21H22N4O8?

CompoundList lists 9 compounds with the molecular formula C21H22N4O8, including Methyl 2,6-bis[(4-nitrobenzoyl)amino]hexanoate, 2-Hydroxynevirapine glucuronide, 8-Hydroxynevirapine glucuronide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C21H22N4O8?

C21H22N4O8 has a degree of unsaturation of 13. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.