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Molecular formula

C21H24FN7O5S

1 compound has this formula on CompoundList.

Molar mass
505.52g/mol
Monoisotopic mass
505.1544Da
Atoms
59
Elements
6
Rings plus double bonds
13

The formula C21H24FN7O5S describes a molecule made of 21 carbon atoms, 24 hydrogen atoms, 1 fluorine atom, 7 nitrogen atoms, 5 oxygen atoms and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2149.89%
    12.011 × 21 = 252.231 g/mol
  • H Hydrogen × 244.79%
    1.008 × 24 = 24.192 g/mol
  • F Fluorine × 13.76%
    18.998 × 1 = 18.998 g/mol
  • N Nitrogen × 719.40%
    14.007 × 7 = 98.049 g/mol
  • O Oxygen × 515.82%
    15.999 × 5 = 79.995 g/mol
  • S Sulfur × 16.34%
    32.06 × 1 = 32.060 g/mol
Look up another formula

Compounds with the formula C21H24FN7O5S

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

(2-Fluoro-4-(methanesulfonyl)phenyl)(6-(4-(3-isopropyl-(1,2,4)oxadiazol-5-yl)piperidin-1-yl)-5-nitropyrimidin-4-yl)amine chemical structure, C21H24FN7O5S, CAS 733750-99-7
(2-Fluoro-4-(methanesulfonyl)phenyl)(6-(4-(3-isopropyl-(1,2,4)oxadiazol-5-yl)piperidin-1-yl)-5-nitropyrimidin-4-yl)amine
CAS 733750-99-7C21H24FN7O5S

Frequently asked questions

What is the molar mass of C21H24FN7O5S?

The molar mass of C21H24FN7O5S is 505.52 g/mol, calculated from standard atomic weights for 21 carbon atoms, 24 hydrogen atoms, 1 fluorine atom, 7 nitrogen atoms, 5 oxygen atoms and 1 sulfur atom. The monoisotopic mass is 505.1544 Da.

How many compounds have the formula C21H24FN7O5S?

CompoundList lists 1 compound with the molecular formula C21H24FN7O5S, including (2-Fluoro-4-(methanesulfonyl)phenyl)(6-(4-(3-isopropyl-(1,2,4)oxadiazol-5-yl)piperidin-1-yl)-5-nitropyrimidin-4-yl)amine. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C21H24FN7O5S?

C21H24FN7O5S has a degree of unsaturation of 13. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.