CompoundList
Molecular formula

C21H25BO5

7 compounds have this formula on CompoundList.

Molar mass
368.24g/mol
Monoisotopic mass
368.1795Da
Atoms
52
Elements
4

The formula C21H25BO5 describes a molecule made of 21 carbon atoms, 25 hydrogen atoms, 1 boron atom and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2168.50%
    12.011 × 21 = 252.231 g/mol
  • H Hydrogen × 256.84%
    1.008 × 25 = 25.200 g/mol
  • B Boron × 12.94%
    10.81 × 1 = 10.810 g/mol
  • O Oxygen × 521.72%
    15.999 × 5 = 79.995 g/mol
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Compounds with the formula C21H25BO5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 7 of 7 compounds

Frequently asked questions

What is the molar mass of C21H25BO5?

The molar mass of C21H25BO5 is 368.24 g/mol, calculated from standard atomic weights for 21 carbon atoms, 25 hydrogen atoms, 1 boron atom and 5 oxygen atoms. The monoisotopic mass is 368.1795 Da.

How many compounds have the formula C21H25BO5?

CompoundList lists 7 compounds with the molecular formula C21H25BO5, including 3-Benzyloxy-4-methoxycarbonylphenylboronic acid pinacol ester, Methyl 4-((4-(4,4,5,5-tetramethyl-1,3,2-dioxaborolan-2-yl)phenoxy)methyl)benzoate, Phenyl-[4-(4,4,5,5-tetramethyl-[1,3,2]dioxaborolan-2-yl)-phenoxy]-acetic acid methyl ester. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.