C21H28FNO
8 compounds have this formula on CompoundList.
- Molar mass
- 329.46g/mol
- Monoisotopic mass
- 334.2469Da
- Atoms
- 52
- Elements
- 5
- Rings plus double bonds
- 8
The formula C21H28FNO describes a molecule made of 21 carbon atoms, 28 hydrogen atoms, 1 fluorine atom, 1 nitrogen atom and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2176.56%12.011 × 21 = 252.231 g/mol
- H Hydrogen × 288.57%1.008 × 28 = 28.224 g/mol
- F Fluorine × 15.77%18.998 × 1 = 18.998 g/mol
- N Nitrogen × 14.25%14.007 × 1 = 14.007 g/mol
- O Oxygen × 14.86%15.999 × 1 = 15.999 g/mol
Compounds with the formula C21H28FNO
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 8 of 8 compounds
![[2,4,5,6,7-Pentadeuterio-1-(5-fluoropentyl)indol-3-yl]-(2,2,3,3-tetramethylcyclopropyl)methanone chemical structure, C21H28FNO, CAS 2095544-37-7](/s/PXLDPUUMIHVLEC-OAWGXGCBSA-N.svg)
Frequently asked questions
What is the molar mass of C21H28FNO?
The molar mass of C21H28FNO is 329.46 g/mol, calculated from standard atomic weights for 21 carbon atoms, 28 hydrogen atoms, 1 fluorine atom, 1 nitrogen atom and 1 oxygen atom. The monoisotopic mass is 334.2469 Da.
How many compounds have the formula C21H28FNO?
CompoundList lists 8 compounds with the molecular formula C21H28FNO, including Xlr 11, Xlr-11 N-(2-fluoropentyl) isomer, 4-Fluorohexbutinol. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C21H28FNO?
C21H28FNO has a degree of unsaturation of 8. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.