CompoundList
Molecular formula

C21H38N2O6

3 compounds have this formula on CompoundList.

Molar mass
414.54g/mol
Monoisotopic mass
414.2730Da
Atoms
67
Elements
4
Rings plus double bonds
4

The formula C21H38N2O6 describes a molecule made of 21 carbon atoms, 38 hydrogen atoms, 2 nitrogen atoms and 6 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2160.85%
    12.011 × 21 = 252.231 g/mol
  • H Hydrogen × 389.24%
    1.008 × 38 = 38.304 g/mol
  • N Nitrogen × 26.76%
    14.007 × 2 = 28.014 g/mol
  • O Oxygen × 623.16%
    15.999 × 6 = 95.994 g/mol
Look up another formula

Compounds with the formula C21H38N2O6

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 3 of 3 compounds

Frequently asked questions

What is the molar mass of C21H38N2O6?

The molar mass of C21H38N2O6 is 414.54 g/mol, calculated from standard atomic weights for 21 carbon atoms, 38 hydrogen atoms, 2 nitrogen atoms and 6 oxygen atoms. The monoisotopic mass is 414.2730 Da.

How many compounds have the formula C21H38N2O6?

CompoundList lists 3 compounds with the molecular formula C21H38N2O6, including Pentanedioic acid, 1,5-bis[2-[2-(1-methylethyl)-3-oxazolidinyl]ethyl] ester, N-[(2S)-3-Hydroxy-1-[[(2S)-1-[(2R)-2-(hydroxymethyl)oxiran-2-yl]-4-methyl-1-oxopentan-2-yl]amino]-1-oxopropan-2-yl]-7-methyloctanamide, (2S)-2-{[(tert-Butoxy)carbonyl]amino}butanedioic acid, dicyclohexylamine. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C21H38N2O6?

C21H38N2O6 has a degree of unsaturation of 4. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.