CompoundList
Molecular formula

C21H39N5O4

1 compound has this formula on CompoundList.

Molar mass
425.57g/mol
Monoisotopic mass
425.3002Da
Atoms
69
Elements
4
Rings plus double bonds
5

The formula C21H39N5O4 describes a molecule made of 21 carbon atoms, 39 hydrogen atoms, 5 nitrogen atoms and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2159.27%
    12.011 × 21 = 252.231 g/mol
  • H Hydrogen × 399.24%
    1.008 × 39 = 39.312 g/mol
  • N Nitrogen × 516.46%
    14.007 × 5 = 70.035 g/mol
  • O Oxygen × 415.04%
    15.999 × 4 = 63.996 g/mol
Look up another formula

Compounds with the formula C21H39N5O4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C21H39N5O4?

The molar mass of C21H39N5O4 is 425.57 g/mol, calculated from standard atomic weights for 21 carbon atoms, 39 hydrogen atoms, 5 nitrogen atoms and 4 oxygen atoms. The monoisotopic mass is 425.3002 Da.

How many compounds have the formula C21H39N5O4?

CompoundList lists 1 compound with the molecular formula C21H39N5O4, including Butanoic acid, 4-azido-2-[[(1,1-dimethylethoxy)carbonyl]amino]-, (2S)-, compd. with N-cyclohexylcyclohexanamine (1:1). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C21H39N5O4?

C21H39N5O4 has a degree of unsaturation of 5. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.