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Molecular formula

C21H45BO12

1 compound has this formula on CompoundList.

Molar mass
500.39g/mol
Monoisotopic mass
500.3004Da
Atoms
79
Elements
4

The formula C21H45BO12 describes a molecule made of 21 carbon atoms, 45 hydrogen atoms, 1 boron atom and 12 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2150.41%
    12.011 × 21 = 252.231 g/mol
  • H Hydrogen × 459.06%
    1.008 × 45 = 45.360 g/mol
  • B Boron × 12.16%
    10.81 × 1 = 10.810 g/mol
  • O Oxygen × 1238.37%
    15.999 × 12 = 191.988 g/mol
Look up another formula

Compounds with the formula C21H45BO12

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Tris[2-[2-(2-methoxyethoxy)ethoxy]ethyl] orthoborate chemical structure, C21H45BO12, CAS 30989-05-0
Tris[2-[2-(2-methoxyethoxy)ethoxy]ethyl] orthoborate
CAS 30989-05-0C21H45BO12

Frequently asked questions

What is the molar mass of C21H45BO12?

The molar mass of C21H45BO12 is 500.39 g/mol, calculated from standard atomic weights for 21 carbon atoms, 45 hydrogen atoms, 1 boron atom and 12 oxygen atoms. The monoisotopic mass is 500.3004 Da.

How many compounds have the formula C21H45BO12?

CompoundList lists 1 compound with the molecular formula C21H45BO12, including Tris[2-[2-(2-methoxyethoxy)ethoxy]ethyl] orthoborate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.