CompoundList
Molecular formula

C22H13N3O4

11 compounds have this formula on CompoundList.

Molar mass
383.36g/mol
Monoisotopic mass
383.0906Da
Atoms
42
Elements
4
Rings plus double bonds
18

The formula C22H13N3O4 describes a molecule made of 22 carbon atoms, 13 hydrogen atoms, 3 nitrogen atoms and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2268.93%
    12.011 × 22 = 264.242 g/mol
  • H Hydrogen × 133.42%
    1.008 × 13 = 13.104 g/mol
  • N Nitrogen × 310.96%
    14.007 × 3 = 42.021 g/mol
  • O Oxygen × 416.69%
    15.999 × 4 = 63.996 g/mol
Look up another formula

Compounds with the formula C22H13N3O4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 11 of 11 compounds

Frequently asked questions

What is the molar mass of C22H13N3O4?

The molar mass of C22H13N3O4 is 383.36 g/mol, calculated from standard atomic weights for 22 carbon atoms, 13 hydrogen atoms, 3 nitrogen atoms and 4 oxygen atoms. The monoisotopic mass is 383.0906 Da.

How many compounds have the formula C22H13N3O4?

CompoundList lists 11 compounds with the molecular formula C22H13N3O4, including 2-(8-Methylquinolin-5-yl)-6-nitrobenzo[de]isoquinoline-1,3-dione, 2-[4-(1H-Benzimidazol-2-yl)phenyl]-1,3-dioxo-2,3-dihydro-1H-isoindole-5-carboxylic acid, 5-(4-Oxo-3,1-benzoxazin-2-yl)-2-(pyridin-3-ylmethyl)isoindole-1,3-dione. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C22H13N3O4?

C22H13N3O4 has a degree of unsaturation of 18. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.