CompoundList
Molecular formula

C22H19ClN4O5

7 compounds have this formula on CompoundList.

Molar mass
454.87g/mol
Monoisotopic mass
454.1044Da
Atoms
51
Elements
5
Rings plus double bonds
15

The formula C22H19ClN4O5 describes a molecule made of 22 carbon atoms, 19 hydrogen atoms, 1 chlorine atom, 4 nitrogen atoms and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2258.09%
    12.011 × 22 = 264.242 g/mol
  • H Hydrogen × 194.21%
    1.008 × 19 = 19.152 g/mol
  • Cl Chlorine × 17.79%
    35.45 × 1 = 35.450 g/mol
  • N Nitrogen × 412.32%
    14.007 × 4 = 56.028 g/mol
  • O Oxygen × 517.59%
    15.999 × 5 = 79.995 g/mol
Look up another formula

Compounds with the formula C22H19ClN4O5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 7 of 7 compounds

Frequently asked questions

What is the molar mass of C22H19ClN4O5?

The molar mass of C22H19ClN4O5 is 454.87 g/mol, calculated from standard atomic weights for 22 carbon atoms, 19 hydrogen atoms, 1 chlorine atom, 4 nitrogen atoms and 5 oxygen atoms. The monoisotopic mass is 454.1044 Da.

How many compounds have the formula C22H19ClN4O5?

CompoundList lists 7 compounds with the molecular formula C22H19ClN4O5, including Tivozanib, N-{4-[4-(4-Chlorobenzoyl)-1-piperazinyl]phenyl}-5-nitro-2-furamide, N-[2-[4-(4-Chlorobenzoyl)piperazin-1-yl]phenyl]-5-nitrofuran-2-carboxamide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C22H19ClN4O5?

C22H19ClN4O5 has a degree of unsaturation of 15. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.