CompoundList
Molecular formula

C22H25N5O7

8 compounds have this formula on CompoundList.

Molar mass
471.47g/mol
Monoisotopic mass
471.1754Da
Atoms
59
Elements
4
Rings plus double bonds
13

The formula C22H25N5O7 describes a molecule made of 22 carbon atoms, 25 hydrogen atoms, 5 nitrogen atoms and 7 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2256.05%
    12.011 × 22 = 264.242 g/mol
  • H Hydrogen × 255.34%
    1.008 × 25 = 25.200 g/mol
  • N Nitrogen × 514.85%
    14.007 × 5 = 70.035 g/mol
  • O Oxygen × 723.75%
    15.999 × 7 = 111.993 g/mol
Look up another formula

Compounds with the formula C22H25N5O7

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 8 of 8 compounds

Frequently asked questions

What is the molar mass of C22H25N5O7?

The molar mass of C22H25N5O7 is 471.47 g/mol, calculated from standard atomic weights for 22 carbon atoms, 25 hydrogen atoms, 5 nitrogen atoms and 7 oxygen atoms. The monoisotopic mass is 471.1754 Da.

How many compounds have the formula C22H25N5O7?

CompoundList lists 8 compounds with the molecular formula C22H25N5O7, including beta-Alanine, N-(3-(acetylamino)-4-(2-(4-nitrophenyl)diazenyl)phenyl)-N-(3-methoxy-3-oxopropyl)-, methyl ester, N-[5-[Bis[2-(acetyloxy)ethyl]amino]-2-[2-(4-nitrophenyl)diazenyl]phenyl]acetamide, C.I. Disperse Red 74. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C22H25N5O7?

C22H25N5O7 has a degree of unsaturation of 13. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.