C22H31Cl2N2NaO4
1 compound has this formula on CompoundList.
- Molar mass
- 481.39g/mol
- Monoisotopic mass
- 480.1559Da
- Atoms
- 62
- Elements
- 6
The formula C22H31Cl2N2NaO4 describes a molecule made of 22 carbon atoms, 31 hydrogen atoms, 2 chlorine atoms, 2 nitrogen atoms, 1 sodium atom and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2254.89%12.011 × 22 = 264.242 g/mol
- H Hydrogen × 316.49%1.008 × 31 = 31.248 g/mol
- Cl Chlorine × 214.73%35.45 × 2 = 70.900 g/mol
- N Nitrogen × 25.82%14.007 × 2 = 28.014 g/mol
- Na Sodium × 14.78%22.99 × 1 = 22.990 g/mol
- O Oxygen × 413.29%15.999 × 4 = 63.996 g/mol
Compounds with the formula C22H31Cl2N2NaO4
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C22H31Cl2N2NaO4?
The molar mass of C22H31Cl2N2NaO4 is 481.39 g/mol, calculated from standard atomic weights for 22 carbon atoms, 31 hydrogen atoms, 2 chlorine atoms, 2 nitrogen atoms, 1 sodium atom and 4 oxygen atoms. The monoisotopic mass is 480.1559 Da.
How many compounds have the formula C22H31Cl2N2NaO4?
CompoundList lists 1 compound with the molecular formula C22H31Cl2N2NaO4, including Lorglumide sodium. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.