C23H15BBr2F4O
1 compound has this formula on CompoundList.
- Molar mass
- 553.98g/mol
- Monoisotopic mass
- 551.9519Da
- Atoms
- 46
- Elements
- 6
The formula C23H15BBr2F4O describes a molecule made of 23 carbon atoms, 15 hydrogen atoms, 1 boron atom, 2 bromine atoms, 4 fluorine atoms and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2349.87%12.011 × 23 = 276.253 g/mol
- H Hydrogen × 152.73%1.008 × 15 = 15.120 g/mol
- B Boron × 11.95%10.81 × 1 = 10.810 g/mol
- Br Bromine × 228.85%79.904 × 2 = 159.808 g/mol
- F Fluorine × 413.72%18.998 × 4 = 75.992 g/mol
- O Oxygen × 12.89%15.999 × 1 = 15.999 g/mol
Compounds with the formula C23H15BBr2F4O
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C23H15BBr2F4O?
The molar mass of C23H15BBr2F4O is 553.98 g/mol, calculated from standard atomic weights for 23 carbon atoms, 15 hydrogen atoms, 1 boron atom, 2 bromine atoms, 4 fluorine atoms and 1 oxygen atom. The monoisotopic mass is 551.9519 Da.
How many compounds have the formula C23H15BBr2F4O?
CompoundList lists 1 compound with the molecular formula C23H15BBr2F4O, including 2,6-Bis(4-bromophenyl)-4-phenylpyran-1-ylium tetrafluoroborate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.