CompoundList
Molecular formula

C23H19ClN2

10 compounds have this formula on CompoundList.

Molar mass
358.87g/mol
Monoisotopic mass
358.1237Da
Atoms
45
Elements
4
Rings plus double bonds
15

The formula C23H19ClN2 describes a molecule made of 23 carbon atoms, 19 hydrogen atoms, 1 chlorine atom and 2 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2376.98%
    12.011 × 23 = 276.253 g/mol
  • H Hydrogen × 195.34%
    1.008 × 19 = 19.152 g/mol
  • Cl Chlorine × 19.88%
    35.45 × 1 = 35.450 g/mol
  • N Nitrogen × 27.81%
    14.007 × 2 = 28.014 g/mol
Look up another formula

Compounds with the formula C23H19ClN2

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 10 of 10 compounds

Frequently asked questions

What is the molar mass of C23H19ClN2?

The molar mass of C23H19ClN2 is 358.87 g/mol, calculated from standard atomic weights for 23 carbon atoms, 19 hydrogen atoms, 1 chlorine atom and 2 nitrogen atoms. The monoisotopic mass is 358.1237 Da.

How many compounds have the formula C23H19ClN2?

CompoundList lists 10 compounds with the molecular formula C23H19ClN2, including 4-(Chloromethyl)-1-trityl-1H-imidazole, 2-(4-Chlorophenyl)-3-phenyl-5-[(E)-2-phenylethenyl]-3,4-dihydropyrazole, 2-Methyl-1H-imidazole clotrimazole. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C23H19ClN2?

C23H19ClN2 has a degree of unsaturation of 15. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.