C23H20F3IO5
1 compound has this formula on CompoundList.
- Molar mass
- 560.30g/mol
- Monoisotopic mass
- 560.0308Da
- Atoms
- 52
- Elements
- 5
- Rings plus double bonds
- 12
The formula C23H20F3IO5 describes a molecule made of 23 carbon atoms, 20 hydrogen atoms, 3 fluorine atoms, 1 iodine atom and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2349.30%12.011 × 23 = 276.253 g/mol
- H Hydrogen × 203.60%1.008 × 20 = 20.160 g/mol
- F Fluorine × 310.17%18.998 × 3 = 56.994 g/mol
- I Iodine × 122.65%126.9 × 1 = 126.900 g/mol
- O Oxygen × 514.28%15.999 × 5 = 79.995 g/mol
Compounds with the formula C23H20F3IO5
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C23H20F3IO5?
The molar mass of C23H20F3IO5 is 560.30 g/mol, calculated from standard atomic weights for 23 carbon atoms, 20 hydrogen atoms, 3 fluorine atoms, 1 iodine atom and 5 oxygen atoms. The monoisotopic mass is 560.0308 Da.
How many compounds have the formula C23H20F3IO5?
CompoundList lists 1 compound with the molecular formula C23H20F3IO5, including 6-Ethyl-3-(4-iodophenoxy)-4-oxo-2-(trifluoromethyl)-4H-chromen-7-yl pivalate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C23H20F3IO5?
C23H20F3IO5 has a degree of unsaturation of 12. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.