CompoundList
Molecular formula

C23H27N7

11 compounds have this formula on CompoundList.

Molar mass
401.52g/mol
Monoisotopic mass
401.2328Da
Atoms
57
Elements
3
Rings plus double bonds
14

The formula C23H27N7 describes a molecule made of 23 carbon atoms, 27 hydrogen atoms and 7 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2368.80%
    12.011 × 23 = 276.253 g/mol
  • H Hydrogen × 276.78%
    1.008 × 27 = 27.216 g/mol
  • N Nitrogen × 724.42%
    14.007 × 7 = 98.049 g/mol
Look up another formula

Compounds with the formula C23H27N7

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 11 of 11 compounds

Frequently asked questions

What is the molar mass of C23H27N7?

The molar mass of C23H27N7 is 401.52 g/mol, calculated from standard atomic weights for 23 carbon atoms, 27 hydrogen atoms and 7 nitrogen atoms. The monoisotopic mass is 401.2328 Da.

How many compounds have the formula C23H27N7?

CompoundList lists 11 compounds with the molecular formula C23H27N7, including 4-(3,4-Dihydro-2H-quinolin-1-yl)-6-[(4-phenyl-1-piperazinyl)methyl]-1,3,5-triazin-2-amine, PR5-LL-CM01, 3-[3-(4-Pyridin-2-ylmethyl-piperazin-1-yl)-propyl]-5-[1,2,4]triazol-4-yl-1H-indole. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C23H27N7?

C23H27N7 has a degree of unsaturation of 14. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.