CompoundList
Molecular formula

C23H28O11

13 compounds have this formula on CompoundList.

Molar mass
480.47g/mol
Monoisotopic mass
480.1632Da
Atoms
62
Elements
3
Rings plus double bonds
10

The formula C23H28O11 describes a molecule made of 23 carbon atoms, 28 hydrogen atoms and 11 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2357.50%
    12.011 × 23 = 276.253 g/mol
  • H Hydrogen × 285.87%
    1.008 × 28 = 28.224 g/mol
  • O Oxygen × 1136.63%
    15.999 × 11 = 175.989 g/mol
Look up another formula

Compounds with the formula C23H28O11

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 13 of 13 compounds

Frequently asked questions

What is the molar mass of C23H28O11?

The molar mass of C23H28O11 is 480.47 g/mol, calculated from standard atomic weights for 23 carbon atoms, 28 hydrogen atoms and 11 oxygen atoms. The monoisotopic mass is 480.1632 Da.

How many compounds have the formula C23H28O11?

CompoundList lists 13 compounds with the molecular formula C23H28O11, including Paeoniflorin, Albiflorin, Methyl (11beta,12alpha,15beta)-15-(acetyloxy)-13,20-epoxy-3,11,12-trihydroxy-2,16-dioxopicras-3-en-21-oate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C23H28O11?

C23H28O11 has a degree of unsaturation of 10. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.