CompoundList
Molecular formula

C23H31ClN4O4S2

9 compounds have this formula on CompoundList.

Molar mass
527.10g/mol
Monoisotopic mass
526.1475Da
Atoms
65
Elements
6
Rings plus double bonds
10

The formula C23H31ClN4O4S2 describes a molecule made of 23 carbon atoms, 31 hydrogen atoms, 1 chlorine atom, 4 nitrogen atoms, 4 oxygen atoms and 2 sulfur atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2352.41%
    12.011 × 23 = 276.253 g/mol
  • H Hydrogen × 315.93%
    1.008 × 31 = 31.248 g/mol
  • Cl Chlorine × 16.73%
    35.45 × 1 = 35.450 g/mol
  • N Nitrogen × 410.63%
    14.007 × 4 = 56.028 g/mol
  • O Oxygen × 412.14%
    15.999 × 4 = 63.996 g/mol
  • S Sulfur × 212.16%
    32.06 × 2 = 64.120 g/mol
Look up another formula

Compounds with the formula C23H31ClN4O4S2

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 9 of 9 compounds

Frequently asked questions

What is the molar mass of C23H31ClN4O4S2?

The molar mass of C23H31ClN4O4S2 is 527.10 g/mol, calculated from standard atomic weights for 23 carbon atoms, 31 hydrogen atoms, 1 chlorine atom, 4 nitrogen atoms, 4 oxygen atoms and 2 sulfur atoms. The monoisotopic mass is 526.1475 Da.

How many compounds have the formula C23H31ClN4O4S2?

CompoundList lists 9 compounds with the molecular formula C23H31ClN4O4S2, including N-(3-(Dimethylamino)propyl)-4-(N,N-dimethylsulfamoyl)-N-(4-methoxy-7-methylbenzo[d]thiazol-2-yl)benzamide hydrochloride, 6-Isopropyl-2-(4-(piperidin-1-ylsulfonyl)benzamido)-4,5,6,7-tetrahydrothieno[2,3-c]pyridine-3-carboxamide hydrochloride, 6-Ethyl-2-(4-((4-methylpiperidin-1-yl)sulfonyl)benzamido)-4,5,6,7-tetrahydrothieno[2,3-c]pyridine-3-carboxamide hydrochloride. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C23H31ClN4O4S2?

C23H31ClN4O4S2 has a degree of unsaturation of 10. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.