C24H12BrF39Sn
1 compound has this formula on CompoundList.
- Molar mass
- 1239.90g/mol
- Monoisotopic mass
- 1239.8522Da
- Atoms
- 77
- Elements
- 5
The formula C24H12BrF39Sn describes a molecule made of 24 carbon atoms, 12 hydrogen atoms, 1 bromine atom, 39 fluorine atoms and 1 tin atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2423.25%12.011 × 24 = 288.264 g/mol
- H Hydrogen × 120.98%1.008 × 12 = 12.096 g/mol
- Br Bromine × 16.44%79.904 × 1 = 79.904 g/mol
- F Fluorine × 3959.76%18.998 × 39 = 740.922 g/mol
- Sn Tin × 19.57%118.71 × 1 = 118.710 g/mol
Compounds with the formula C24H12BrF39Sn
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C24H12BrF39Sn?
The molar mass of C24H12BrF39Sn is 1239.90 g/mol, calculated from standard atomic weights for 24 carbon atoms, 12 hydrogen atoms, 1 bromine atom, 39 fluorine atoms and 1 tin atom. The monoisotopic mass is 1239.8522 Da.
How many compounds have the formula C24H12BrF39Sn?
CompoundList lists 1 compound with the molecular formula C24H12BrF39Sn, including Tris(3,3,4,4,5,5,6,6,7,7,8,8,8-tridecafluorooctyl)tin bromide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.