CompoundList
Molecular formula

C24H15N3

3 compounds have this formula on CompoundList.

Molar mass
345.41g/mol
Monoisotopic mass
345.1266Da
Atoms
42
Elements
3
Rings plus double bonds
19

The formula C24H15N3 describes a molecule made of 24 carbon atoms, 15 hydrogen atoms and 3 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2483.46%
    12.011 × 24 = 288.264 g/mol
  • H Hydrogen × 154.38%
    1.008 × 15 = 15.120 g/mol
  • N Nitrogen × 312.17%
    14.007 × 3 = 42.021 g/mol
Look up another formula

Compounds with the formula C24H15N3

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 3 of 3 compounds

Frequently asked questions

What is the molar mass of C24H15N3?

The molar mass of C24H15N3 is 345.41 g/mol, calculated from standard atomic weights for 24 carbon atoms, 15 hydrogen atoms and 3 nitrogen atoms. The monoisotopic mass is 345.1266 Da.

How many compounds have the formula C24H15N3?

CompoundList lists 3 compounds with the molecular formula C24H15N3, including 10,15-Dihydro-5H-diindolo(3,2-a:3',2'-c)carbazole, 5H-Diindolo[3,2-a:2',3'-c]carbazole, 6,11-dihydro-, 14,15-Dihydro-13H-pyrrolo[2,3-a:5,4-a']dicarbazole. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C24H15N3?

C24H15N3 has a degree of unsaturation of 19. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.