C24H28BrP
4 compounds have this formula on CompoundList.
- Molar mass
- 427.37g/mol
- Monoisotopic mass
- 431.1426Da
- Atoms
- 54
- Elements
- 4
- Rings plus double bonds
- 11
The formula C24H28BrP describes a molecule made of 24 carbon atoms, 28 hydrogen atoms, 1 bromine atom and 1 phosphorus atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2467.45%12.011 × 24 = 288.264 g/mol
- H Hydrogen × 286.60%1.008 × 28 = 28.224 g/mol
- Br Bromine × 118.70%79.904 × 1 = 79.904 g/mol
- P Phosphorus × 17.25%30.974 × 1 = 30.974 g/mol
Compounds with the formula C24H28BrP
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 4 of 4 compounds
Frequently asked questions
What is the molar mass of C24H28BrP?
The molar mass of C24H28BrP is 427.37 g/mol, calculated from standard atomic weights for 24 carbon atoms, 28 hydrogen atoms, 1 bromine atom and 1 phosphorus atom. The monoisotopic mass is 431.1426 Da.
How many compounds have the formula C24H28BrP?
CompoundList lists 4 compounds with the molecular formula C24H28BrP, including Phosphonium, hexyltriphenyl-, bromide (1:1), Phosphonium, (4-methylpentyl)triphenyl-, bromide, n-Hexyl-5,5,6,6,6-d5-triphenylphosphonium Bromide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C24H28BrP?
C24H28BrP has a degree of unsaturation of 11. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.