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Molecular formula

C24H31NO5Si

2 compounds have this formula on CompoundList.

Molar mass
441.60g/mol
Monoisotopic mass
441.1972Da
Atoms
62
Elements
5
Rings plus double bonds
11

The formula C24H31NO5Si describes a molecule made of 24 carbon atoms, 31 hydrogen atoms, 1 nitrogen atom, 5 oxygen atoms and 1 silicon atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2465.28%
    12.011 × 24 = 288.264 g/mol
  • H Hydrogen × 317.08%
    1.008 × 31 = 31.248 g/mol
  • N Nitrogen × 13.17%
    14.007 × 1 = 14.007 g/mol
  • O Oxygen × 518.11%
    15.999 × 5 = 79.995 g/mol
  • Si Silicon × 16.36%
    28.085 × 1 = 28.085 g/mol
Look up another formula

Compounds with the formula C24H31NO5Si

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 2 of 2 compounds

(2S)-3-[(tert-Butyldimethylsilyl)oxy]-2-{[(9H-fluoren-9-ylmethoxy)carbonyl]amino}propanoic acid chemical structure, C24H31NO5Si, CAS 146346-81-8
(2S)-3-[(tert-Butyldimethylsilyl)oxy]-2-{[(9H-fluoren-9-ylmethoxy)carbonyl]amino}propanoic acid
CAS 146346-81-8C24H31NO5Si
Fmoc-D-Ser(BSi)-OH chemical structure, C24H31NO5Si, CAS 201210-25-5
Fmoc-D-Ser(BSi)-OH
CAS 201210-25-5C24H31NO5Si

Frequently asked questions

What is the molar mass of C24H31NO5Si?

The molar mass of C24H31NO5Si is 441.60 g/mol, calculated from standard atomic weights for 24 carbon atoms, 31 hydrogen atoms, 1 nitrogen atom, 5 oxygen atoms and 1 silicon atom. The monoisotopic mass is 441.1972 Da.

How many compounds have the formula C24H31NO5Si?

CompoundList lists 2 compounds with the molecular formula C24H31NO5Si, including (2S)-3-[(tert-Butyldimethylsilyl)oxy]-2-{[(9H-fluoren-9-ylmethoxy)carbonyl]amino}propanoic acid, Fmoc-D-Ser(BSi)-OH. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C24H31NO5Si?

C24H31NO5Si has a degree of unsaturation of 11. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.