C254H416N72O75S10
1 compound has this formula on CompoundList.
- Molar mass
- 5999.15g/mol
- Monoisotopic mass
- 5994.8158Da
- Atoms
- 827
- Elements
- 5
- Rings plus double bonds
- 83
The formula C254H416N72O75S10 describes a molecule made of 254 carbon atoms, 416 hydrogen atoms, 72 nitrogen atoms, 75 oxygen atoms and 10 sulfur atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 25450.85%12.011 × 254 = 3050.794 g/mol
- H Hydrogen × 4166.99%1.008 × 416 = 419.328 g/mol
- N Nitrogen × 7216.81%14.007 × 72 = 1008.504 g/mol
- O Oxygen × 7520.00%15.999 × 75 = 1199.925 g/mol
- S Sulfur × 105.34%32.06 × 10 = 320.600 g/mol
Compounds with the formula C254H416N72O75S10
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C254H416N72O75S10?
The molar mass of C254H416N72O75S10 is 5999.15 g/mol, calculated from standard atomic weights for 254 carbon atoms, 416 hydrogen atoms, 72 nitrogen atoms, 75 oxygen atoms and 10 sulfur atoms. The monoisotopic mass is 5994.8158 Da.
How many compounds have the formula C254H416N72O75S10?
CompoundList lists 1 compound with the molecular formula C254H416N72O75S10, including Tiprelestat. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C254H416N72O75S10?
C254H416N72O75S10 has a degree of unsaturation of 83. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.