CompoundList
Molecular formula

C25H24BrNO5

7 compounds have this formula on CompoundList.

Molar mass
498.37g/mol
Monoisotopic mass
497.0838Da
Atoms
56
Elements
5
Rings plus double bonds
14

The formula C25H24BrNO5 describes a molecule made of 25 carbon atoms, 24 hydrogen atoms, 1 bromine atom, 1 nitrogen atom and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2560.25%
    12.011 × 25 = 300.275 g/mol
  • H Hydrogen × 244.85%
    1.008 × 24 = 24.192 g/mol
  • Br Bromine × 116.03%
    79.904 × 1 = 79.904 g/mol
  • N Nitrogen × 12.81%
    14.007 × 1 = 14.007 g/mol
  • O Oxygen × 516.05%
    15.999 × 5 = 79.995 g/mol
Look up another formula

Compounds with the formula C25H24BrNO5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 7 of 7 compounds

Frequently asked questions

What is the molar mass of C25H24BrNO5?

The molar mass of C25H24BrNO5 is 498.37 g/mol, calculated from standard atomic weights for 25 carbon atoms, 24 hydrogen atoms, 1 bromine atom, 1 nitrogen atom and 5 oxygen atoms. The monoisotopic mass is 497.0838 Da.

How many compounds have the formula C25H24BrNO5?

CompoundList lists 7 compounds with the molecular formula C25H24BrNO5, including Methyl 4-(3-bromo-4,5-diethoxyphenyl)-2-methyl-5-oxo-4,5-dihydro-1H-indeno[1,2-b]pyridine-3-carboxylate, Methyl 4-(2-bromo-4,5-diethoxyphenyl)-2-methyl-5-oxo-4,5-dihydro-1H-indeno[1,2-b]pyridine-3-carboxylate, Benzyl 4-(3-bromo-4-hydroxy-5-methoxyphenyl)-2-methyl-5-oxo-1,4,5,6,7,8-hexahydroquinoline-3-carboxylate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C25H24BrNO5?

C25H24BrNO5 has a degree of unsaturation of 14. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.