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Molecular formula

C25H28FN5O5

1 compound has this formula on CompoundList.

Molar mass
497.53g/mol
Monoisotopic mass
497.2074Da
Atoms
64
Elements
5
Rings plus double bonds
14

The formula C25H28FN5O5 describes a molecule made of 25 carbon atoms, 28 hydrogen atoms, 1 fluorine atom, 5 nitrogen atoms and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2560.35%
    12.011 × 25 = 300.275 g/mol
  • H Hydrogen × 285.67%
    1.008 × 28 = 28.224 g/mol
  • F Fluorine × 13.82%
    18.998 × 1 = 18.998 g/mol
  • N Nitrogen × 514.08%
    14.007 × 5 = 70.035 g/mol
  • O Oxygen × 516.08%
    15.999 × 5 = 79.995 g/mol
Look up another formula

Compounds with the formula C25H28FN5O5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

N-(4-Fluorophenyl)-2-(3-hydroxypropyl)-5-methyl-7-(3,4,5-trimethoxyphenyl)-1,7-dihydro-[1,2,4]triazolo[1,5-a]pyrimidine-6-carboxamide chemical structure, C25H28FN5O5, CAS 537699-98-2
N-(4-Fluorophenyl)-2-(3-hydroxypropyl)-5-methyl-7-(3,4,5-trimethoxyphenyl)-1,7-dihydro-[1,2,4]triazolo[1,5-a]pyrimidine-6-carboxamide
CAS 537699-98-2C25H28FN5O5

Frequently asked questions

What is the molar mass of C25H28FN5O5?

The molar mass of C25H28FN5O5 is 497.53 g/mol, calculated from standard atomic weights for 25 carbon atoms, 28 hydrogen atoms, 1 fluorine atom, 5 nitrogen atoms and 5 oxygen atoms. The monoisotopic mass is 497.2074 Da.

How many compounds have the formula C25H28FN5O5?

CompoundList lists 1 compound with the molecular formula C25H28FN5O5, including N-(4-Fluorophenyl)-2-(3-hydroxypropyl)-5-methyl-7-(3,4,5-trimethoxyphenyl)-1,7-dihydro-[1,2,4]triazolo[1,5-a]pyrimidine-6-carboxamide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C25H28FN5O5?

C25H28FN5O5 has a degree of unsaturation of 14. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.