CompoundList
Molecular formula

C25H31ClN2O4

11 compounds have this formula on CompoundList.

Molar mass
458.98g/mol
Monoisotopic mass
458.1972Da
Atoms
63
Elements
5
Rings plus double bonds
11

The formula C25H31ClN2O4 describes a molecule made of 25 carbon atoms, 31 hydrogen atoms, 1 chlorine atom, 2 nitrogen atoms and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2565.42%
    12.011 × 25 = 300.275 g/mol
  • H Hydrogen × 316.81%
    1.008 × 31 = 31.248 g/mol
  • Cl Chlorine × 17.72%
    35.45 × 1 = 35.450 g/mol
  • N Nitrogen × 26.10%
    14.007 × 2 = 28.014 g/mol
  • O Oxygen × 413.94%
    15.999 × 4 = 63.996 g/mol
Look up another formula

Compounds with the formula C25H31ClN2O4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 11 of 11 compounds

Frequently asked questions

What is the molar mass of C25H31ClN2O4?

The molar mass of C25H31ClN2O4 is 458.98 g/mol, calculated from standard atomic weights for 25 carbon atoms, 31 hydrogen atoms, 1 chlorine atom, 2 nitrogen atoms and 4 oxygen atoms. The monoisotopic mass is 458.1972 Da.

How many compounds have the formula C25H31ClN2O4?

CompoundList lists 11 compounds with the molecular formula C25H31ClN2O4, including Iptacopan hydrochloride anhydrous, Rlh 033, 4-(2-Decanoylcarbohydrazonoyl)-2-methoxyphenyl 2-chlorobenzoate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C25H31ClN2O4?

C25H31ClN2O4 has a degree of unsaturation of 11. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.