C264H406N80O77S3
1 compound has this formula on CompoundList.
- Molar mass
- 6028.81g/mol
- Monoisotopic mass
- 6024.9475Da
- Atoms
- 830
- Elements
- 5
- Rings plus double bonds
- 102
The formula C264H406N80O77S3 describes a molecule made of 264 carbon atoms, 406 hydrogen atoms, 80 nitrogen atoms, 77 oxygen atoms and 3 sulfur atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 26452.60%12.011 × 264 = 3170.904 g/mol
- H Hydrogen × 4066.79%1.008 × 406 = 409.248 g/mol
- N Nitrogen × 8018.59%14.007 × 80 = 1120.560 g/mol
- O Oxygen × 7720.43%15.999 × 77 = 1231.923 g/mol
- S Sulfur × 31.60%32.06 × 3 = 96.180 g/mol
Compounds with the formula C264H406N80O77S3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C264H406N80O77S3?
The molar mass of C264H406N80O77S3 is 6028.81 g/mol, calculated from standard atomic weights for 264 carbon atoms, 406 hydrogen atoms, 80 nitrogen atoms, 77 oxygen atoms and 3 sulfur atoms. The monoisotopic mass is 6024.9475 Da.
How many compounds have the formula C264H406N80O77S3?
CompoundList lists 1 compound with the molecular formula C264H406N80O77S3, including Adrenomedullin (human). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C264H406N80O77S3?
C264H406N80O77S3 has a degree of unsaturation of 102. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.