C26H24FNO
4 compounds have this formula on CompoundList.
- Molar mass
- 385.48g/mol
- Monoisotopic mass
- 385.1842Da
- Atoms
- 53
- Elements
- 5
- Rings plus double bonds
- 15
The formula C26H24FNO describes a molecule made of 26 carbon atoms, 24 hydrogen atoms, 1 fluorine atom, 1 nitrogen atom and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2681.01%12.011 × 26 = 312.286 g/mol
- H Hydrogen × 246.28%1.008 × 24 = 24.192 g/mol
- F Fluorine × 14.93%18.998 × 1 = 18.998 g/mol
- N Nitrogen × 13.63%14.007 × 1 = 14.007 g/mol
- O Oxygen × 14.15%15.999 × 1 = 15.999 g/mol
Compounds with the formula C26H24FNO
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 4 of 4 compounds
Frequently asked questions
What is the molar mass of C26H24FNO?
The molar mass of C26H24FNO is 385.48 g/mol, calculated from standard atomic weights for 26 carbon atoms, 24 hydrogen atoms, 1 fluorine atom, 1 nitrogen atom and 1 oxygen atom. The monoisotopic mass is 385.1842 Da.
How many compounds have the formula C26H24FNO?
CompoundList lists 4 compounds with the molecular formula C26H24FNO, including Jwh 307, Jwh-368, (5-(4-Fluorophenyl)-1-pentyl-1H-pyrrol-3-yl)(naphthalen-1-yl)methanone. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C26H24FNO?
C26H24FNO has a degree of unsaturation of 15. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.