CompoundList
Molecular formula

C26H35N7O4

2 compounds have this formula on CompoundList.

Molar mass
509.61g/mol
Monoisotopic mass
509.2751Da
Atoms
72
Elements
4
Rings plus double bonds
13

The formula C26H35N7O4 describes a molecule made of 26 carbon atoms, 35 hydrogen atoms, 7 nitrogen atoms and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2661.28%
    12.011 × 26 = 312.286 g/mol
  • H Hydrogen × 356.92%
    1.008 × 35 = 35.280 g/mol
  • N Nitrogen × 719.24%
    14.007 × 7 = 98.049 g/mol
  • O Oxygen × 412.56%
    15.999 × 4 = 63.996 g/mol
Look up another formula

Compounds with the formula C26H35N7O4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 2 of 2 compounds

Frequently asked questions

What is the molar mass of C26H35N7O4?

The molar mass of C26H35N7O4 is 509.61 g/mol, calculated from standard atomic weights for 26 carbon atoms, 35 hydrogen atoms, 7 nitrogen atoms and 4 oxygen atoms. The monoisotopic mass is 509.2751 Da.

How many compounds have the formula C26H35N7O4?

CompoundList lists 2 compounds with the molecular formula C26H35N7O4, including 2-Imino-10-methyl-N-[2-(4-morpholinyl)ethyl]-1-[3-(4-morpholinyl)propyl]-5-oxo-1,5-dihydro-2H-dipyrido[1,2-A:2,3-D]pyrimidine-3-carboxamide, RE 102. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C26H35N7O4?

C26H35N7O4 has a degree of unsaturation of 13. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.