C27H21Br
5 compounds have this formula on CompoundList.
- Molar mass
- 425.37g/mol
- Monoisotopic mass
- 424.0827Da
- Atoms
- 49
- Elements
- 3
- Rings plus double bonds
- 17
The formula C27H21Br describes a molecule made of 27 carbon atoms, 21 hydrogen atoms and 1 bromine atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2776.24%12.011 × 27 = 324.297 g/mol
- H Hydrogen × 214.98%1.008 × 21 = 21.168 g/mol
- Br Bromine × 118.78%79.904 × 1 = 79.904 g/mol
Compounds with the formula C27H21Br
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 5 of 5 compounds
Frequently asked questions
What is the molar mass of C27H21Br?
The molar mass of C27H21Br is 425.37 g/mol, calculated from standard atomic weights for 27 carbon atoms, 21 hydrogen atoms and 1 bromine atom. The monoisotopic mass is 424.0827 Da.
How many compounds have the formula C27H21Br?
CompoundList lists 5 compounds with the molecular formula C27H21Br, including (2-(4-(Bromomethyl)phenyl)ethene-1,1,2-triyl)tribenzene, 2-Bromo-1,1,3,3-tetraphenyl-1-propene, 2-Bromo-9,9-di-p-tolyl-9H-fluorene. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C27H21Br?
C27H21Br has a degree of unsaturation of 17. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.