C27H31F5N4O
1 compound has this formula on CompoundList.
- Molar mass
- 522.56g/mol
- Monoisotopic mass
- 522.2418Da
- Atoms
- 68
- Elements
- 5
- Rings plus double bonds
- 12
The formula C27H31F5N4O describes a molecule made of 27 carbon atoms, 31 hydrogen atoms, 5 fluorine atoms, 4 nitrogen atoms and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2762.06%12.011 × 27 = 324.297 g/mol
- H Hydrogen × 315.98%1.008 × 31 = 31.248 g/mol
- F Fluorine × 518.18%18.998 × 5 = 94.990 g/mol
- N Nitrogen × 410.72%14.007 × 4 = 56.028 g/mol
- O Oxygen × 13.06%15.999 × 1 = 15.999 g/mol
Compounds with the formula C27H31F5N4O
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C27H31F5N4O?
The molar mass of C27H31F5N4O is 522.56 g/mol, calculated from standard atomic weights for 27 carbon atoms, 31 hydrogen atoms, 5 fluorine atoms, 4 nitrogen atoms and 1 oxygen atom. The monoisotopic mass is 522.2418 Da.
How many compounds have the formula C27H31F5N4O?
CompoundList lists 1 compound with the molecular formula C27H31F5N4O, including Giredestrant. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C27H31F5N4O?
C27H31F5N4O has a degree of unsaturation of 12. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.