C27H40O11
3 compounds have this formula on CompoundList.
- Molar mass
- 540.61g/mol
- Monoisotopic mass
- 540.2571Da
- Atoms
- 78
- Elements
- 3
- Rings plus double bonds
- 8
The formula C27H40O11 describes a molecule made of 27 carbon atoms, 40 hydrogen atoms and 11 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2759.99%12.011 × 27 = 324.297 g/mol
- H Hydrogen × 407.46%1.008 × 40 = 40.320 g/mol
- O Oxygen × 1132.55%15.999 × 11 = 175.989 g/mol
Compounds with the formula C27H40O11
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 3 of 3 compounds
Frequently asked questions
What is the molar mass of C27H40O11?
The molar mass of C27H40O11 is 540.61 g/mol, calculated from standard atomic weights for 27 carbon atoms, 40 hydrogen atoms and 11 oxygen atoms. The monoisotopic mass is 540.2571 Da.
How many compounds have the formula C27H40O11?
CompoundList lists 3 compounds with the molecular formula C27H40O11, including 18,21-Dihydroxy-20-oxo-11,18-epoxypregnan-3-yl hexopyranosiduronic acid, Tetrahydrocortisone 3-(beta-D-glucuronide), Ivhd-valtrate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C27H40O11?
C27H40O11 has a degree of unsaturation of 8. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.