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Molecular formula

C28H24ClNO5

1 compound has this formula on CompoundList.

Molar mass
489.95g/mol
Monoisotopic mass
489.1343Da
Atoms
59
Elements
5
Rings plus double bonds
17

The formula C28H24ClNO5 describes a molecule made of 28 carbon atoms, 24 hydrogen atoms, 1 chlorine atom, 1 nitrogen atom and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2868.64%
    12.011 × 28 = 336.308 g/mol
  • H Hydrogen × 244.94%
    1.008 × 24 = 24.192 g/mol
  • Cl Chlorine × 17.24%
    35.45 × 1 = 35.450 g/mol
  • N Nitrogen × 12.86%
    14.007 × 1 = 14.007 g/mol
  • O Oxygen × 516.33%
    15.999 × 5 = 79.995 g/mol
Look up another formula

Compounds with the formula C28H24ClNO5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

2-(4-Chlorophenyl)-2-oxoethyl 2-(1,3-dioxooctahydro-4,6-ethenocyclopropa[f]isoindol-2(1H)-yl)-3-phenylpropanoate chemical structure, C28H24ClNO5, CAS 473805-36-6
2-(4-Chlorophenyl)-2-oxoethyl 2-(1,3-dioxooctahydro-4,6-ethenocyclopropa[f]isoindol-2(1H)-yl)-3-phenylpropanoate
CAS 473805-36-6C28H24ClNO5

Frequently asked questions

What is the molar mass of C28H24ClNO5?

The molar mass of C28H24ClNO5 is 489.95 g/mol, calculated from standard atomic weights for 28 carbon atoms, 24 hydrogen atoms, 1 chlorine atom, 1 nitrogen atom and 5 oxygen atoms. The monoisotopic mass is 489.1343 Da.

How many compounds have the formula C28H24ClNO5?

CompoundList lists 1 compound with the molecular formula C28H24ClNO5, including 2-(4-Chlorophenyl)-2-oxoethyl 2-(1,3-dioxooctahydro-4,6-ethenocyclopropa[f]isoindol-2(1H)-yl)-3-phenylpropanoate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C28H24ClNO5?

C28H24ClNO5 has a degree of unsaturation of 17. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.