C28H27ClF5NO
2 compounds have this formula on CompoundList.
- Molar mass
- 523.97g/mol
- Monoisotopic mass
- 523.1701Da
- Atoms
- 63
- Elements
- 6
- Rings plus double bonds
- 13
The formula C28H27ClF5NO describes a molecule made of 28 carbon atoms, 27 hydrogen atoms, 1 chlorine atom, 5 fluorine atoms, 1 nitrogen atom and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2864.18%12.011 × 28 = 336.308 g/mol
- H Hydrogen × 275.19%1.008 × 27 = 27.216 g/mol
- Cl Chlorine × 16.77%35.45 × 1 = 35.450 g/mol
- F Fluorine × 518.13%18.998 × 5 = 94.990 g/mol
- N Nitrogen × 12.67%14.007 × 1 = 14.007 g/mol
- O Oxygen × 13.05%15.999 × 1 = 15.999 g/mol
Compounds with the formula C28H27ClF5NO
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 2 of 2 compounds
Frequently asked questions
What is the molar mass of C28H27ClF5NO?
The molar mass of C28H27ClF5NO is 523.97 g/mol, calculated from standard atomic weights for 28 carbon atoms, 27 hydrogen atoms, 1 chlorine atom, 5 fluorine atoms, 1 nitrogen atom and 1 oxygen atom. The monoisotopic mass is 523.1701 Da.
How many compounds have the formula C28H27ClF5NO?
CompoundList lists 2 compounds with the molecular formula C28H27ClF5NO, including Penfluridol, 4-(4-Chloro-3-(trifluoromethyl)phenyl)-1-(4-(2-fluorophenyl)-4-(4-fluorophenyl)butyl)piperidin-4-ol. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C28H27ClF5NO?
C28H27ClF5NO has a degree of unsaturation of 13. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.