CompoundList
Molecular formula

C29H24O5

8 compounds have this formula on CompoundList.

Molar mass
452.51g/mol
Monoisotopic mass
452.1624Da
Atoms
58
Elements
3
Rings plus double bonds
18

The formula C29H24O5 describes a molecule made of 29 carbon atoms, 24 hydrogen atoms and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2976.98%
    12.011 × 29 = 348.319 g/mol
  • H Hydrogen × 245.35%
    1.008 × 24 = 24.192 g/mol
  • O Oxygen × 517.68%
    15.999 × 5 = 79.995 g/mol
Look up another formula

Compounds with the formula C29H24O5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 8 of 8 compounds

Frequently asked questions

What is the molar mass of C29H24O5?

The molar mass of C29H24O5 is 452.51 g/mol, calculated from standard atomic weights for 29 carbon atoms, 24 hydrogen atoms and 5 oxygen atoms. The monoisotopic mass is 452.1624 Da.

How many compounds have the formula C29H24O5?

CompoundList lists 8 compounds with the molecular formula C29H24O5, including Chamuvaritin, Isochamuvaritin, 1,8-Bis[(4-hydroxyphenyl)methyl]-4-methoxyphenanthrene-2,7-diol. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C29H24O5?

C29H24O5 has a degree of unsaturation of 18. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.