C29H29BNOP2Ru
1 compound has this formula on CompoundList.
- Molar mass
- 581.38g/mol
- Monoisotopic mass
- 582.0861Da
- Atoms
- 64
- Elements
- 7
The formula C29H29BNOP2Ru describes a molecule made of 29 carbon atoms, 29 hydrogen atoms, 1 boron atom, 1 nitrogen atom, 1 oxygen atom, 2 phosphorus atoms and 1 ruthenium atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2959.91%12.011 × 29 = 348.319 g/mol
- H Hydrogen × 295.03%1.008 × 29 = 29.232 g/mol
- B Boron × 11.86%10.81 × 1 = 10.810 g/mol
- N Nitrogen × 12.41%14.007 × 1 = 14.007 g/mol
- O Oxygen × 12.75%15.999 × 1 = 15.999 g/mol
- P Phosphorus × 210.66%30.974 × 2 = 61.948 g/mol
- Ru Ruthenium × 117.38%101.07 × 1 = 101.070 g/mol
Compounds with the formula C29H29BNOP2Ru
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C29H29BNOP2Ru?
The molar mass of C29H29BNOP2Ru is 581.38 g/mol, calculated from standard atomic weights for 29 carbon atoms, 29 hydrogen atoms, 1 boron atom, 1 nitrogen atom, 1 oxygen atom, 2 phosphorus atoms and 1 ruthenium atom. The monoisotopic mass is 582.0861 Da.
How many compounds have the formula C29H29BNOP2Ru?
CompoundList lists 1 compound with the molecular formula C29H29BNOP2Ru, including Carbonylhydrido(tetrahydroborato)(bis(2-diphenylphosphinoethyl)amino)ruthenium(II). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.