C31H32BN3O
1 compound has this formula on CompoundList.
- Molar mass
- 473.43g/mol
- Monoisotopic mass
- 473.2638Da
- Atoms
- 68
- Elements
- 5
The formula C31H32BN3O describes a molecule made of 31 carbon atoms, 32 hydrogen atoms, 1 boron atom, 3 nitrogen atoms and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 3178.65%12.011 × 31 = 372.341 g/mol
- H Hydrogen × 326.81%1.008 × 32 = 32.256 g/mol
- B Boron × 12.28%10.81 × 1 = 10.810 g/mol
- N Nitrogen × 38.88%14.007 × 3 = 42.021 g/mol
- O Oxygen × 13.38%15.999 × 1 = 15.999 g/mol
Compounds with the formula C31H32BN3O
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C31H32BN3O?
The molar mass of C31H32BN3O is 473.43 g/mol, calculated from standard atomic weights for 31 carbon atoms, 32 hydrogen atoms, 1 boron atom, 3 nitrogen atoms and 1 oxygen atom. The monoisotopic mass is 473.2638 Da.
How many compounds have the formula C31H32BN3O?
CompoundList lists 1 compound with the molecular formula C31H32BN3O, including 3-((Dimethylamino)carbonyl)-1-methyl-1H-imidazol-3-ium tetraphenylborate(1-). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.