CompoundList
Molecular formula

C31H34O12

4 compounds have this formula on CompoundList.

Molar mass
598.60g/mol
Monoisotopic mass
598.2050Da
Atoms
77
Elements
3
Rings plus double bonds
15

The formula C31H34O12 describes a molecule made of 31 carbon atoms, 34 hydrogen atoms and 12 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 3162.20%
    12.011 × 31 = 372.341 g/mol
  • H Hydrogen × 345.73%
    1.008 × 34 = 34.272 g/mol
  • O Oxygen × 1232.07%
    15.999 × 12 = 191.988 g/mol
Look up another formula

Compounds with the formula C31H34O12

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 4 of 4 compounds

Frequently asked questions

What is the molar mass of C31H34O12?

The molar mass of C31H34O12 is 598.60 g/mol, calculated from standard atomic weights for 31 carbon atoms, 34 hydrogen atoms and 12 oxygen atoms. The monoisotopic mass is 598.2050 Da.

How many compounds have the formula C31H34O12?

CompoundList lists 4 compounds with the molecular formula C31H34O12, including Landomycin D, Paeonidanin A, Suffrupaeonidanin D. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C31H34O12?

C31H34O12 has a degree of unsaturation of 15. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.