CompoundList
Molecular formula

C31H38N4

3 compounds have this formula on CompoundList.

Molar mass
466.67g/mol
Monoisotopic mass
466.3096Da
Atoms
73
Elements
3
Rings plus double bonds
15

The formula C31H38N4 describes a molecule made of 31 carbon atoms, 38 hydrogen atoms and 4 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 3179.79%
    12.011 × 31 = 372.341 g/mol
  • H Hydrogen × 388.21%
    1.008 × 38 = 38.304 g/mol
  • N Nitrogen × 412.01%
    14.007 × 4 = 56.028 g/mol
Look up another formula

Compounds with the formula C31H38N4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 3 of 3 compounds

Frequently asked questions

What is the molar mass of C31H38N4?

The molar mass of C31H38N4 is 466.67 g/mol, calculated from standard atomic weights for 31 carbon atoms, 38 hydrogen atoms and 4 nitrogen atoms. The monoisotopic mass is 466.3096 Da.

How many compounds have the formula C31H38N4?

CompoundList lists 3 compounds with the molecular formula C31H38N4, including Buterizine, Benzenamine, 4-(2-(5-(4-(diethylamino)phenyl)-4,5-dihydro-1-phenyl-1H-pyrazol-3-yl)ethenyl)-N,N-diethyl-, 2-Benzyl-3-methyl-1-(undecylamino)pyrido[1,2-a]benzimidazole-4-carbonitrile. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C31H38N4?

C31H38N4 has a degree of unsaturation of 15. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.